第6回小問模試・第7問 答え

$$ \begin{align} &(8a^3b^2+4a^2b^2)\div(2ab)^2\\ &=(8a^3b^2+4a^2b^2)\div(4a^2b^2)\\ &=\frac{8a^3b^2}{4a^2b^2}+\frac{4a^2b^2}{4a^2b^2}\\ &=2a+1 \end{align} $$